Web300 J of work is done in sliding a 2 kg block up an inclined plane of height 10 m. Work done against friction is (Take g = 10 m/s2) (a) 1000 J. (b) 100 J. (c) 100 J. (d). Web#neet #workpowerenergy #class11physics Web300 j Solution: Given: Work done in sliding a block up an inclined plane W = 320 Joule Mass of block M = 2 k g Height of inclined plane = 10 m The potential energy stored in the block.
300j Of Work Is Done In Sliding A 2kg, 300 J of work is done in sliding a 2 kg block up an inclined plane of height 10 m. Work done against, 2.56 MB, 01:52, 3,553, Ritesh Dahiya Sir - (KDC) Kota Doubt Counter, 2020-08-22T13:05:29.000000Z, 19, 300j work is done in sliding a 2kg block up an inclined plane of height, neetlab.com, 600 x 300, jpeg, 2kg 300j, 20, 300j-of-work-is-done-in-sliding-a-2kg, KAMPION
WebClick here 👆 to get an answer to your question ️ 300J of work is done in sliding a 2kg block up and inclined plane of hight 10m. Work done against friction is… WebQ. 300 J of work is done in sliding up a 2 kg block on an inclined plane to a height of 10 m. Taking value of acceleration due to gravity g to be 10 m s − 2 , work done against friction. Web300 J of work is done in sliding a 2 kg block up an inclined plane of height 10 m. Taking g =10 m / s 2, work done against friction is Taking g =10 m / s 2, work done against friction. WebBrowse by Stream ... ... Web`300 J`of work is done in slide a `2kg` block up an inclined plane of height `10m`. `Taking g = 10 m//s^(2), work done against friction is WebThe total work done on the block is 300J Total work= work done against gravity + work done against friction Work done against gravity= mgh= 2*10*10=200J So. Web300J 300 J of work is done in slide a 2kg 2 k g block up an inclined plane of height 10m 10 m. `Taking g = 10 m//s^ (2), work done against friction is. 300J 300 J of. Web300 J of work is done in sliding a 2 kg block up an inclined plane of height 10 m. Taking g = 10 m/s 2 , work done against friction is (a) 1001 (b) Zero (c) 1000 J (d) 200 J. 300 J of.
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